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THEOREM OF THE DAY Miquel's Triangle Theorem Let A, B and C be the vertices of a triangle and a, b and c be points chosen on sides CB, AC and AB, respectively. Then the circles defined by bAc, cBa and aCb have a common point of intersection. Moreover, if a, b and c are chosen to be collinear then this point lies on the circle defined by A, B and C. |
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Auguste Miquel was a French mathematician active in the mid-nineteenth century. The point of intersection of the circles in this theorem is known as the 'Miquel Point'. Web link: www-math.mit.edu/~kedlaya/geometryunbound/geom-080399.pdf (360K, see section 1.2) Further reading: Episodes
in Nineteenth and Twentieth Century Euclidean Geometry |
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Theorem of the Day is produced and maintained
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